cos^4x - sin^4x = 1- 2sin^2x
(cos²-sin²)(cos²+sin²)=(cos²-sin²)*1=1-sin²-sin²=1-2sin²
P=L
w drugim brakuje =
odp. w zał.
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cos^4x - sin^4x = 1- 2sin^2x
(cos²-sin²)(cos²+sin²)=(cos²-sin²)*1=1-sin²-sin²=1-2sin²
P=L
w drugim brakuje =
odp. w zał.