November 2018 1 19 Report
Sprawdź czy rozwiązaniem układu równań $$\left\{\begin{array}{rcl}  5+2x&=&-y+z\\  4z&=&\frac{x+1}{2}+3y\\  2x+\frac{z}{2}&=&3y+1  \end{array} \right.$$ są liczby $$\left\{\begin{array}{rcl}  x&=&-2\frac{91}{167}\\ \\  y&=&-1\frac{7}{167}\\ \\  z&=&-1\frac{128}{167}  \end{array} \right.$$.
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