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Vo = 40 m/s
α = 60°
g = 10 m/s²
waktu yang diperlukan ??? diperlukan untuk apa ?
jangkauan maksimum
X = Vo² sin 2 / g
= 40² sin 120° / 10
= 80√3 m ← jwb
tinggi maksimum
Y = Vo² sin²α / 2g
= 40² sin²60° / (2 · 10)
= 60 m ← jwb