rozwiąż układ równań ( matematyka nowa era str.361 zad 1)
a) { y=8-x
{ x²+y²-8y=0
b) { y=x-2
{ x²+y²-6x-16=0
Pomocy potrzebuje tego
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
a) x^2 + (8-x)^2 - 8(8-x) =0
x^2 + 64 - 16x + x^2 - 64 + 8x = 0
2x^2 - 8x = 0
delta = 64
pierwiastek z delty = 8
x1 = (8-8)/4 = 0
x2 = (8+8)/4 = 16/4=4
x=0 lub x=4
b) x^2 + (x-2)^2 -6x - 16 = 0
x^2 + x^2 -4x + 4 - 6x -16 = 0
2x^2 - 10x - 12 = 0 /2
x^2 - 5x - 6 = 0
delta = 25 + 24 = 49
pierwiastek z delty = 7
x1 = (5-7)/2 = -2/2 = -1
x2 = (5+7)/2 = 12/2 = 6
x=-1 lub x=6