Rozwiąż rownanie
a) x^2 - 81 = 0
b) x^2 +3x +4 = 0
c) x^2 +4x +4 = 0
Potrzebane wzory:
Δ = b²-ac
x₁ = -b -√Δ/2a
x₂ = -b + √Δ/2a
a)
x² - 81 = 0
(x+9)(x-9) = 0
x = -9 ∨ x = 9
b)
x² + 3x + 4 = 0
Δ = 3² - 4 x 1 x 4 = 9 - 16 = -7
Δ < 0 więc równanie nie ma rozwiązań
c)
x² + 4x + 4 = 0
Δ = 4² - 4 x 1 x 4 = 16 - 16 = 0
√Δ = √0 = 0
x = -(-4)/2*1 = -2
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Pozdrawiam :)
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Potrzebane wzory:
Δ = b²-ac
x₁ = -b -√Δ/2a
x₂ = -b + √Δ/2a
a)
x² - 81 = 0
(x+9)(x-9) = 0
x = -9 ∨ x = 9
b)
x² + 3x + 4 = 0
Δ = 3² - 4 x 1 x 4 = 9 - 16 = -7
Δ < 0 więc równanie nie ma rozwiązań
c)
x² + 4x + 4 = 0
Δ = 4² - 4 x 1 x 4 = 16 - 16 = 0
√Δ = √0 = 0
x = -(-4)/2*1 = -2
----------------------------------------------------------------------------------------------------------
Feci, quod potui, faciant meliora potentes
Pozdrawiam :)