Rozwiąż równanie:
a) (x-5)^2=x^2=15 b)-(2a-5)^2=(1-2a)(1+2a)
a) (x-5)^2= x^2+15
x^2-10x+25=x^2+15
-10x=-10 / : (-10)
x=1
b)
-(2a-5)^2=(1-2a)(1+2a)
-(4a^2-20a+25)=1-4a^2
-4a^2+20a-25=1-4a^2
20a=26 / :20
a=1,3
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a) (x-5)^2= x^2+15
x^2-10x+25=x^2+15
-10x=-10 / : (-10)
x=1
b)
-(2a-5)^2=(1-2a)(1+2a)
-(4a^2-20a+25)=1-4a^2
-4a^2+20a-25=1-4a^2
20a=26 / :20
a=1,3