Question

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(8-y)^2=

(7+x)^2=

(4+x) (4-x)=

(8-4y)^2=

(7y+x)^2=

(4+5x) (4-5x)=

(8y-y^4)^2=

(7y+3x^5)^2=

(x+4y^3)(4y^3-x)=

(-6-y)^2=

Answer 1

Answer 2

(8-y)^2= 64 - 16y + y²

(7+x)^2= 49 + 14x + x²

(4+x) (4-x)= 16 -x²

(8-4y)^2= 64 - 64y + 16y²

(7y+x)^2= 49y² + 14xy + x²

(4+5x) (4-5x)= 16 - 25x²

(8y-y^4)^2= 64y² - 16y⁵ + y⁸

(7y+3x^5)^2= 49y² + 42yx⁵ + 9x¹⁰

(x+4y^3)(4y^3-x)=  16y⁹ - x²

(-6-y)^2= -(6 + y)² = -(36 + 12y + y²) = -36 - 12y - y²