Rozwiąż równanie x(do potegi 3)-7x(do potegi2)-4x+28=0
zapis x^2 oznacza x do potęgi 2
x^3-7x^2-4x+28=0
x^3-4x-7x^2+28=0
x(x^2-4)-7(x^2-4)=0
(x^2-4)(x-7)=0
x^2-4=0 v x=7
x^2=4
x=2 v x=-2
x=2 v x=-2 v x=7
Pozdrawiam.
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zapis x^2 oznacza x do potęgi 2
x^3-7x^2-4x+28=0
x^3-4x-7x^2+28=0
x(x^2-4)-7(x^2-4)=0
(x^2-4)(x-7)=0
x^2-4=0 v x=7
x^2=4
x=2 v x=-2
x=2 v x=-2 v x=7
Pozdrawiam.