a) -x²+5x-6=0 /· (-1)
x²-5x+6=0
Δ=5²-4·1·6
Δ=25-24
Δ=1
√Δ=1
x₁=(-b-√Δ):2a
x₂= (-b+√Δ):2a
x₁= (5-1):2=4:2=2
x₂=(5+1):2=6:2=3
b)- 3(x - 1)2 + 5 = 0
(-3x+3)·2+5=0
-6x+6+5=0
-6x+11=0
-6x=-11 /:(-6)
x=11/6 (jedenaście szóstych)
x= 1i5/6
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a) -x²+5x-6=0 /· (-1)
x²-5x+6=0
Δ=5²-4·1·6
Δ=25-24
Δ=1
√Δ=1
x₁=(-b-√Δ):2a
x₂= (-b+√Δ):2a
x₁= (5-1):2=4:2=2
x₂=(5+1):2=6:2=3
b)
- 3(x - 1)2 + 5 = 0
(-3x+3)·2+5=0
-6x+6+5=0
-6x+11=0
-6x=-11 /:(-6)
x=11/6 (jedenaście szóstych)
x= 1i5/6