Rozwiąż rownania : a) x\x-4 = x-3 b)2\5-x = x\3
x/x-4 = x-3
x=(x-3)(x-4)
x=x²-4x-3x+12
x²-8x+12=0
Δ=64-48=16
√Δ=4
x₁=(8+4)/2=6
x₂=(8-4)/2=2
x∈{6,2}
b)
b)2/5-x = x/3
x(5-x)=6
5x-x²=6
-x²+5x-6=0
Δ=25-24=1
x₁=(-5-1)/-2=3
x₂=(-5+1)/-2=2
x∈{2,3}
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x/x-4 = x-3
x=(x-3)(x-4)
x=x²-4x-3x+12
x²-8x+12=0
Δ=64-48=16
√Δ=4
x₁=(8+4)/2=6
x₂=(8-4)/2=2
x∈{6,2}
b)
b)2/5-x = x/3
x(5-x)=6
5x-x²=6
-x²+5x-6=0
Δ=25-24=1
x₁=(-5-1)/-2=3
x₂=(-5+1)/-2=2
x∈{2,3}