Rozłóż wielomian W(x) na czynniki i podaj jego miejsce zerowe : a) W(x) =2x³-3x²-8x+12 b) W(x)=-3x⁵ +12x³
a)
W(x) =2x³-3x²-8x+12=x²(2x - 3) -4(2x - 3)= (2x -3)(x² -4)=(2x -3)(x- 2)(x+2)
(2x -3)=0 v (x- 2)=0 v (x+2)=0
2x=3
x=3/2 v x=2 v x = -2
b)
W(x)=-3x⁵ +12x³ = -3x³(x² - 4)= -3x³(x - 2)(x +2)
-3x³=0 v (x - 2)=0 v (x +2)=0
x=0 v x=2 v x= -2
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a)
W(x) =2x³-3x²-8x+12=x²(2x - 3) -4(2x - 3)= (2x -3)(x² -4)=(2x -3)(x- 2)(x+2)
(2x -3)=0 v (x- 2)=0 v (x+2)=0
2x=3
x=3/2 v x=2 v x = -2
b)
W(x)=-3x⁵ +12x³ = -3x³(x² - 4)= -3x³(x - 2)(x +2)
-3x³=0 v (x - 2)=0 v (x +2)=0
x=0 v x=2 v x= -2