Question

Prosze o pomoc LOGARYTMY zadanie w zalączniku

Answer 1

1.

log₂x= 0,4

log₂2·x²=log₂2+log₂x²= 1+2log₂x=1+2·0,4=1+0,8=1,8   cnu

 

log₂16·x³=log₂16+log₂x³=4+3log₂x=4+3·0,4=4+1,2=5,2   cnu

 

log₂x⁴:2=log₂x⁴ - log₂2=4log₂x - 1=4·0,4 -1=1,6 -1=0,6  cnu

 

2.

log₃x= -¼

log₃3·x²=log₃3 +log₃x²=1+2log₃x=1+2·(-¼)= 1- ½=½

 

log₃9·x⁸=log₃9+log₃x⁸=2+8log₃x=2+8·(-¼)= 2- 2=0

 

log₃x⁴:81=log₃x⁴ - log₃81=4log₃x - log₃81=4·(-¼) -4= -1-4= -5

 

log₃27·x⁶=log₃27+log₃x⁶=3+ 6log₃x=3+6·(-¼)=3- 3/2= 1,5