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P=(10+4,8)*5 przez 2=37
|AB| = 10cm
|CD| = 4,8cm
h = 5cm
P = ½ x (a+b) x h
P = ½ x (10cm+4,8cm) x 5cm
P = 2,5cm x 14,8cm
P = 37cm²
x- razy
Odp. Pole trapezu wynosi 37cm².