Oblicz pola zacieniowanych figur. Proszę :)
c) P= πr²
P1=6π²
P1= 36π
P1 = 113,04
P2= 4π²
P2 = 16π
P2 = 50,24
Pole zacieniowanej figury = P1 - P2
=113,04 - 50,24
= 62,8
d)P1 = 120/360 * πr²
P1 = 12/36 * π6²
P1 = 12/36 * 3,14 * 36
P1 = 12 * 3,14
P1 = 37,68
P2 = 120/360 * πr²
P2 = 12/36 * 3,14 * 3²
P2 = 12/36 * 3,14 * 9
P2 = 108/36 * 3,14
P2 = 3 * 3,14
P2 = 9,42
Pole figury zacieniowanej = 37,68 - 9,42
= 28,26
e) P1 = π3²
P1 = 3,14 * 9
P1 = 28,26
P2 = π5²
P2 = 3,14 * 25
P2 = 78,25
pole zacieniowanej figury = P1 + P2
= 28,26 + 78,25
= 106,51
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c) P= πr²
P1=6π²
P1= 36π
P1 = 113,04
P2= 4π²
P2 = 16π
P2 = 50,24
Pole zacieniowanej figury = P1 - P2
=113,04 - 50,24
= 62,8
d)P1 = 120/360 * πr²
P1 = 12/36 * π6²
P1 = 12/36 * 3,14 * 36
P1 = 12 * 3,14
P1 = 37,68
P2 = 120/360 * πr²
P2 = 12/36 * 3,14 * 3²
P2 = 12/36 * 3,14 * 9
P2 = 108/36 * 3,14
P2 = 3 * 3,14
P2 = 9,42
Pole figury zacieniowanej = 37,68 - 9,42
= 28,26
e) P1 = π3²
P1 = 3,14 * 9
P1 = 28,26
P2 = π5²
P2 = 3,14 * 25
P2 = 78,25
pole zacieniowanej figury = P1 + P2
= 28,26 + 78,25
= 106,51