Oblicz masę czasteczkową fruktozy i oblicz zawartość procentową wodoru w cząsteczce
C6H12O6=6*12U+1*12U+6*16U=72+12+96=180
180 TO 100 %
12U TO X
X= 12*100%/180=6,(6)%
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C6H12O6=6*12U+1*12U+6*16U=72+12+96=180
180 TO 100 %
12U TO X
X= 12*100%/180=6,(6)%