Niech m=0.3(6) i n=0.(36), liczbę m-n przedstaw w postaci ułamka dziesiętnego okresowego
0.3(6)-0.(36)=0.00(30)
0,3(6) = m
10m = 3,(6)
100m = 36,(6)
100m-10a = 90a
90m = 36,(6)-3,(6)
90m = 33 |:90
m = 33/90 = 11/30
n= 0,(36)
100n = 36,36
100n-n=99b
99n = 36 |:99
n = 4/11
11/30-4/11 = 121/330-120/330 = 1/330
1/330 = 0,00(30)
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0.3(6)-0.(36)=0.00(30)
0,3(6) = m
10m = 3,(6)
100m = 36,(6)
100m-10a = 90a
90m = 36,(6)-3,(6)
90m = 33 |:90
m = 33/90 = 11/30
n= 0,(36)
100n = 36,36
100n-n=99b
99n = 36 |:99
n = 4/11
11/30-4/11 = 121/330-120/330 = 1/330
1/330 = 0,00(30)