napisz równanie symetralnej odcinka AB, gdy:
a) A=(1,2) B=(5,-2)
b) A= (-3,-4) B=(1,0)
c) A=(0,0) B=(3,4)
d) A=(-7,0) B=(-7,4)
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d) (y-0) (-7 - (-7)) = (4-0) (x - (-7))
y = 4x + 7
a2= - 1/4
s= (-7,2)
2= 4 * (-7) + b
b= 30
y = -1/4 x + 30