NA TERAZ!
.w ciagu arytmetycznym a2=8 i a4=4. znajdz a1, r, i sp.
a2 = 8
a4 = 4
an = a1 + (n-1)*r
a1+r = 8
a1+3r = 4
-------------- (-)
3r-r = 4-8
2r = -4 /:2
r = -2
====
a1 = 8-r
a1 = 8-(-2)
a1 = 10
======
Spr.
a2 = 10+(-2) = 10-2 = 8
a4 = 10+3*(-2) = 10-6 = 4
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a2 = 8
a4 = 4
an = a1 + (n-1)*r
a1+r = 8
a1+3r = 4
-------------- (-)
3r-r = 4-8
2r = -4 /:2
r = -2
====
a1 = 8-r
a1 = 8-(-2)
a1 = 10
======
Spr.
a2 = 10+(-2) = 10-2 = 8
a4 = 10+3*(-2) = 10-6 = 4