Question

logarytmy

Answer 1

log 3 [ 27 ] = 3 , bo 3^3 = 27

log 27 [ 3 ] = 1/3 , bo  27^(1/3) = 3

log 2 [ 1/2] = - 1,  bo 2^(-1) = 1/2

log 2 [ p(8)] = log 2 [ 8^(1/2)] = ( 1/2)*log 2 [ 8] = (1/2)*3 = 3/2

log 2[ 8] = 3, bo 2^3 = 8

log 3 [ 81] = 4, bo 3^4 = 81

log 4 [ 1/ p(2)] = log 4[ p(2)^(-1)] = - 1 *log 4 [ p(2)] = - 1* ( 1/4) = - 1/4

bo  4^(1/4) = p(2)

log 4 [ 1/ 1024] = - 5 , bo   4^(-5) = 1 / [ 4^5] = 1/1024

log 10^6 = 6*log 10 = 6*1 = 6

log 0,1 = - 1 , bo 10^(-1) = 1/10 = 0,1

log 100 + log 4 [ 1/8] = 2 + log 2^2 [ 8^(-1)] = 2 + (-1) *(1/2) log 2[8] =

= 2 - 0,5*3= 2 - 1,5 = 0,5

bo   2^3 = 8

log 6 [ 1/36] + log [ p3st( 10)] = - 2 + log [ 10^(1/3)] = - 2 + (1/3)*log [10] =

= - 2 + 1/3 = - 1  2/3

bo  6^( - 2) = 1/[ 6^2] = 1/36 

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