Oblicz pole powierzchni i objetosc walca, ktorego promien podstawy stanowi 60% wysokosc rownej 15cm.
h=15cm
r=60%h=0,6h=0,6*15=9cm
Pc=2Pp+Pb
Pc=2pir^2+2pirh
Pc=2pi(r^2+rh)
Pc=2pi(9^2+9*15)=2pi(81+135)=2pi*216
Pc=432picm^2
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V=Pph
V=pir^2h
V=9^2*15pi=81*15pi
V=1215pi cm^3
Pc = 2Pp + Pb = 2∏r^2 + 2∏rH
V=∏r^2H
H = 15 cm
r = 60% * 15 = 9 cm
Pc = 2*3,14*81 + 2*3,14*9*15 = 508,68 + 847,80 = 1356,48 cm^2
V = 3,14* 81 * 15 = 3815,10 cm^3
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h=15cm
r=60%h=0,6h=0,6*15=9cm
Pc=2Pp+Pb
Pc=2pir^2+2pirh
Pc=2pi(r^2+rh)
Pc=2pi(9^2+9*15)=2pi(81+135)=2pi*216
Pc=432picm^2
-----
V=Pph
V=pir^2h
V=9^2*15pi=81*15pi
V=1215pi cm^3
Pc = 2Pp + Pb = 2∏r^2 + 2∏rH
V=∏r^2H
H = 15 cm
r = 60% * 15 = 9 cm
Pc = 2*3,14*81 + 2*3,14*9*15 = 508,68 + 847,80 = 1356,48 cm^2
V = 3,14* 81 * 15 = 3815,10 cm^3