liczba 2 jest pierwiastekm wielomianu W(X)=x^3-2x^2-ax+1. wyznacz a.
W(2)=0
W(2)=8-4*2-2a+1=0
W(2)=-2a+8-8+1=0
-2a=-1/:(-2)
a=1/2
W(x) = x³-2x²-ax+1
x=2
2³-2*2²-2a+1=0
8-8 -2a+1=0
-2a=-1
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
W(2)=0
W(2)=8-4*2-2a+1=0
W(2)=-2a+8-8+1=0
-2a=-1/:(-2)
a=1/2
W(x) = x³-2x²-ax+1
x=2
2³-2*2²-2a+1=0
8-8 -2a+1=0
-2a=-1
a=1/2