kąt rozwarcia stożka wynosi 60 stopni a jego pp=16pi cm2 oblicz H stożka
γ=60° ----> 1/2γ = 30°
Pp = 16π cm²
H=?
liczę promien :
πr² = 16π /:π
r=4 cm
tg 30° = r/H
√3/3 = 4/H
H = 4/√3/3
H=4 * 3/√3
H=12/√3 * √3/√3
H = 12√3/3
H=4√3 cm
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γ=60° ----> 1/2γ = 30°
Pp = 16π cm²
H=?
liczę promien :
πr² = 16π /:π
r=4 cm
tg 30° = r/H
√3/3 = 4/H
H = 4/√3/3
H=4 * 3/√3
H=12/√3 * √3/√3
H = 12√3/3
H=4√3 cm