iloraz liczby 2 ⅕ oraz 3⅓ zwieksz 100 razy
iloraz liczby 2⅕ oraz 3⅓ zwieksz o 100.
znajdz liczbe cztery razy wieksza od ilorazu liczb 12 i 3⅕
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x=(2 1/5:3 1/3)*100
x=(11/5:10/3)*100
x=(11/5*3/10)*100
x=33/50*100
x=66
x=(2 1/5:3 1/3)+100
x=(11/5:10/3)+100
x=(11/5*3/10)+100
x=33/50+100
x=100 33/50
x=4*(12:3 1/5)
x=4*(12/1:16/5)
x=4*(12/1*5/16)
x=4*15/4
x=15