Hitunglah pH dari 4,9 gram H2SO4
dalam 100 mL larutan (Mr H2SO4 =98)
dalam 100 mL larutan (Mr H2SO4 =98)
Risep
![M= \frac{gr/Mr}{V} \\ \\ = \frac{4,9/98}{0,1}=0,5~M \\ \\ \\ ~[H^+]=a.M \\ \\ =2.5.10^{-1} \\ \\ =1 \\ \\ pH=-log[H^+]=-log1=0](https://tex.z-dn.net/?f=M%3D+%5Cfrac%7Bgr%2FMr%7D%7BV%7D+%5C%5C++%5C%5C+%3D+%5Cfrac%7B4%2C9%2F98%7D%7B0%2C1%7D%3D0%2C5%7EM+%5C%5C++%5C%5C++%5C%5C+%7E%5BH%5E%2B%5D%3Da.M+%5C%5C++%5C%5C+%3D2.5.10%5E%7B-1%7D+%5C%5C++%5C%5C+%3D1+%5C%5C++%5C%5C+pH%3D-log%5BH%5E%2B%5D%3D-log1%3D0++ "M= \frac{gr/Mr}{V} \\ \\ = \frac{4,9/98}{0,1}=0,5~M \\ \\ \\ ~[H^+]=a.M \\ \\ =2.5.10^{-1} \\ \\ =1 \\ \\ pH=-log[H^+]=-log1=0")
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