Do 160g wody wsypano i rozpuszczono 40g mocznika (NH2)2CO . Wyznacz stezenie procentowe mocznika w otrzymanym roztworze .
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M(wody)= 160g
M(mocznik)=40g
M(całości) = 40g + 160 g = 200g
200g- 100%
40g -x = 20%
Naj . prosz.
ms=40g
mr=40g+16g=200g
Cp=?
Cp=ms/mr * 100%
Cp=40g/200g * 100%
Cp=20%