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3k²+6k+4=k+2
3k²+5k+2=0
Δ=25-4*3*2=1
k=1/6(-5-1)=-1 lub k=1/6(-5+1)= -2/3
2m-1=-(3-m)
2m-1=-3+m
2m-m=-3+1
m=-2