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sea u= x²+3
du=2x dx
du/2 =x dx
Sustituyedo en términos de u
4∫(1/u)(du/2)
=(4/2)∫(du/u)
integrando:
=2 ln(u) + c
volviendo a la variable original u= x²+3
=2ln( x²+3) + c