Question

rozwiąż równanie

(2/3)^4x-2 > (9/4)^2x-2

2/3 i 9/4 to ułamki

Answer 1

[(2/3)^4]x-2 > [(9/4)^2]x-2

16/81x-2>81/16x-2

16/81x-81/16x>0

256/1296x-6561/1296x>0

-6305/1296x>0

x<0

(2/3)^[4x-2] > (9/4)^[2x-2]

(3/2^(-1))^[4x-2] > (9/4)^[2x-2]

(9/4^(-1/2))^[4x-2] >(9/4)^[2x-2]

(9/4)^(-1/2*[4x-2]) >(9/4)^[2x-2]

-1/2(4x-2)>2x-2

-2x+1>2x-2

-4x>-3

x<3/4

Answer 2

(2/3)^(4x-2)>(2/3)^(-2(2x-2))

4x-2<-4x+4

8x<6/:8

x<6/8

x<3/4

 

 

a^2=(1/a)^(-2)