Ciąg arytmetyczny
a1=1/3
n=17
Sn=51
Ile wynosi r?
r=?
a17=a1+16r
Sn=(a1+a17)*17/2
51=(1/3+1/3+16r)*17/2 I: 17/2
6=2/3+16r
16r=16/3 I:16
r=1/3
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a1=1/3
n=17
Sn=51
r=?
a17=a1+16r
Sn=(a1+a17)*17/2
51=(1/3+1/3+16r)*17/2 I: 17/2
6=2/3+16r
16r=16/3 I:16
r=1/3