" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
D : 2x² - 2 ≠ 0 /: 2
x² - 1 ≠0
(x - 1)(x + 1) ≠ 0
x - 1 ≠ 0 ∧ x + 1 ≠ 0
x ≠ 1 ∧ x ≠ - 1
D : x ∈ R \ { - 1, 1 }
x³ - 1 = (x - 1)(x² + x + 1)
(x³ - 1)/(2x² - 2) = (x - 1)(x² + x + 1)/ 2(x² - 1) =
= (x - 1)(x² + x + 1)/2(x - 1)(x + 1) =
= 0,5(x² + x + 1)/(x + 1)
2x²-2≠0
2(x²-1)≠0
2(x-1)(x+1)≠0
x≠1 i x≠-1
x³-1/2x²-2 = (x-1)(x²+x+1)/2(x-1)(x+1)=(x²+x+1)/2(x+1)