Czy to zadanie jest dobrze nie powinno wyjść r =2 a a1=0
treść to wyznacz ciag arytmetyczny a2=4 a4=6
Prosze o poprawienie jeśli jest żle
a2=a1+r=2
a4=a1+3r=6
a1+r=2 tu chyba razy -1
a1+3r=6
-a1-r=-2
a1+3r=6
-2r=4/-2
r=-2
a1+r=2
a1-2=2
a1=4
an=a1=(n-1)*r
an=4+(n-1)*-2
an=4-2n+2
an=-2n+6
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JeśIi a2=4 i a4=6 i jest to ciag aryt. to
a2=a1+r ====> a1=4-r
a4=a1+3r ===> 6=4-r+3r => 2r=2 => r=1
a1+1=4 => a1=3
an=a1+(n-1)r=3+(n-1)*1=n+2
Odp.:
a1=3
r=1
an=n+2
a2=4
a4 = 6
a1+r = 4
a1+3r = 6
a1=4-r
2-r+3r=6
2r = 4-2
r=1
a1=4-1=3
an = a1 + (n-1)r
an = 3 + n -1 = 2 + n