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2log3 = a
3log2 = 1/a
= 3log9.5 / 3log2.3
= 3log9 + 3log5 / 3log2 + 3log3
= 3log3² + b / (1/a) + 1
= 2 . 3log3 + b / (1/a) + 1
= 2.1 + b / (1/a) + 1
= 2 + b / (1/a) + 1
= 2 + b / (1+a / a)
= (2a + ab) / (1 + a)