Question

Do wykresu funkcji f(x)=logaX nalezy punkt A=(2^√2;-√2/2) wyznacz a

Answer 1

A=(2^{√2};-√2/2}

log_a(2^√2)=-√2/2

√2*log_a2=-√2/2\;/:√2

log_a2=-1/2

a^{-1/2}=2\;/()^{-2}

a=2^{-2}

a=1/4

Answer 2