1)objętość prostopadłościanu wynosi 125cm³ a jego wysokość będąca najdłuższą krawędzią jest równa 10cm. Wyznacz długość i szerokość podstawy prostopadłościanu, wiedząc że wymiary tej bryły tworzą ciąg geometryczny
2)udowidnij ze nierownosc a²+b²+c²≥ab+bc+ac jest prawdziwa dla dowolnych liczb rzeczywistych a,b i c.
;)
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1)
-krawędź podstawy
-krawędz podstawy
-wysokość


















Obliczam pole podsatwy
Obliczam krawędzie podstawy
Ponieważ wysokość była najdłuższym bokiem więc q>0
2)
Suma liczb nieujemnych jest liczbą nieujemną