Odpowiedź:
Rt= 1,4635 Ω
Ro=0,06 Ω
α=0,0046 K⁻¹
To=0°C
Δt=Rt-Ro/(α*Ro)
Δt=1,4635 Ω-0,06 Ω/(0,0046*0,06 Ω)
Δt=5085,14°C
T=To+Δt
T=0°C+5085,14°C
T=5085,14°C
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Odpowiedź:
Rt= 1,4635 Ω
Ro=0,06 Ω
α=0,0046 K⁻¹
To=0°C
Δt=Rt-Ro/(α*Ro)
Δt=1,4635 Ω-0,06 Ω/(0,0046*0,06 Ω)
Δt=5085,14°C
T=To+Δt
T=0°C+5085,14°C
T=5085,14°C