zapisz w postaci sumy algebraiccznej
(x+4)(x²-4x+16)=
(x²-5x+25)(x+5)=
(4x²+2x+1)(2x-1)=
(x+4)(x²-4x+16)=x³-4x²+16x+4x²-16x+64=x³+64
(x²-5x+25)(x+5)=x³+5x²-5x²-25x+25x+125=x³+125
(4x²+2x+1)(2x-1)=8x³-4x²+2x+4x²-2x+2x-1=8x³-1
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(x+4)(x²-4x+16)=x³-4x²+16x+4x²-16x+64=x³+64
(x²-5x+25)(x+5)=x³+5x²-5x²-25x+25x+125=x³+125
(4x²+2x+1)(2x-1)=8x³-4x²+2x+4x²-2x+2x-1=8x³-1
(x+4)(x²-4x+16)=
(x²-5x+25)(x+5)=
(4x²+2x+1)(2x-1)=