Question

zadanie w załączniku

Nierówności

Answer 1

a)

4/(√3-1) ·(√3+1)/(√3+1) = 4(√3+1)/(3-1) = 4(√3+1)/2 = 2(√3+1) = 2+2√3

 

b)

2/(2-√3)·(2+√3)/(2+√3) = 2(2+√3)/(2-3) = 2(2+√3)/(-1) = -2(2+√3) = -4-2√3

 

c)

2/(2√3-4)·(2√3+4)/(2√3+4) = 2(2√3+4)/(12-16) = (4√3+8)/(-4) = -2-√3

 

d)

2√3/(√3+1) ·(√3-1)/(√3-1) = 2√3(√3-1)/(3-1) = (6-2√3)/2 = 3-√3