z funkcji; (x+5) (x+1)
przejdż na funkcje ogólną
i to samo dla funkcji (x-1)(x+3)
f(x) = ( x + 5)*( x + 1)
czyli f(x) = x^2 + x + 5 x + 5
Odp. f(x) = x^2 + 6 x + 5
======================
f(x) = (x - 1)*( x + 3)
czyli f(x) = x^2 + 3 x - x - 3
Odp, f(x) = x^2 + 2 x - 3
=========================
f(x)=(x+5) (x+1)
f(x)= x^2+x+5x+5
f(x)= x^2+6x+5
f(x)=(x-1)(x+3)
f(x) =x^2+3x-x-3
f(x)=x^2+2x-3
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f(x) = ( x + 5)*( x + 1)
czyli f(x) = x^2 + x + 5 x + 5
Odp. f(x) = x^2 + 6 x + 5
======================
f(x) = (x - 1)*( x + 3)
czyli f(x) = x^2 + 3 x - x - 3
Odp, f(x) = x^2 + 2 x - 3
=========================
f(x)=(x+5) (x+1)
f(x)= x^2+x+5x+5
f(x)= x^2+6x+5
f(x)=(x-1)(x+3)
f(x) =x^2+3x-x-3
f(x)=x^2+2x-3