Wyznacz pierwiastki wielomianu
=x³-8x²+8x²-8=x³-8=(x-2)(x²+2x+4)
x-2=0
x=2
x²+2x+4=0
Δ=4-4*1*4=4-16=-12<0 - brak pierwiastkow
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=x³-8x²+8x²-8=x³-8=(x-2)(x²+2x+4)
x-2=0
x=2
x²+2x+4=0
Δ=4-4*1*4=4-16=-12<0 - brak pierwiastkow
licze na naj