Rozwiaz
2x^3 + x^2 - 8x - 4 = 0
x^2(2x + 1) - 4(2x + 1) = 0
(2x + 1) (x^2 - 4) = 0
(2x + 1)(x - 2)(x +2) = 0
2x + 1 = 0 lub x - 2 = 0 lub x + 2 = 0
x = -1/2 x = 2 x = -2
2x³+x²-8x-4=0
x²(2x+1)-4(2x+1)=0
(2x+1)(x²-4)=0
(2x+1)(x-2)(x+2)=0
x=-1\2 x=2 x=-2 D=R\[-2; -1\2;2]
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2x^3 + x^2 - 8x - 4 = 0
x^2(2x + 1) - 4(2x + 1) = 0
(2x + 1) (x^2 - 4) = 0
(2x + 1)(x - 2)(x +2) = 0
2x + 1 = 0 lub x - 2 = 0 lub x + 2 = 0
x = -1/2 x = 2 x = -2
2x³+x²-8x-4=0
x²(2x+1)-4(2x+1)=0
(2x+1)(x²-4)=0
(2x+1)(x-2)(x+2)=0
x=-1\2 x=2 x=-2 D=R\[-2; -1\2;2]