wyznacz miejsce zerowe funkcji f(x)= log₃(3x-5) + 3
f(x)= log₃(3x-5) + 3
D:
3x - 5 > 0
3x > 5
x > 5/3
x > 1 i 2/3
log₃(3x-5) + 3 = 0
log₃ (3x - 5) = - 3
log₃ (3x -5) = log₃ 3^(-3)
3x - 5 = (1/3)^3
3x = 5 + 1/27
3x = 5 i 1/27
3x = 136/27
x = 136/27 * 1/3
x = 136/81
x = 1 i 55/81 ∈ D ----- odpowiedź
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f(x)= log₃(3x-5) + 3
D:
3x - 5 > 0
3x > 5
x > 5/3
x > 1 i 2/3
log₃(3x-5) + 3 = 0
log₃ (3x - 5) = - 3
log₃ (3x -5) = log₃ 3^(-3)
3x - 5 = (1/3)^3
3x = 5 + 1/27
3x = 5 i 1/27
3x = 136/27
x = 136/27 * 1/3
x = 136/81
x = 1 i 55/81 ∈ D ----- odpowiedź