Wyznacz a i b wielomianu , wiedząc, że
W(x) = a x^3 + 4x - b
W(0) = - 3
W( - 2) = 1
zatem
a*0^3 + 4*0 - b = - 3
a*(-2)^3 + 4*(-2) - b = 1
---------------------------------
b = 3
------------
- 8 a - 8 - 3 = 1
- 8 a = 12
a = - 12/8 = -1,5
----------------------
Odp. a = - 1,5; b = 3
==============================
-3=a * 0³+4 *0-b
-3=-0
b=3
.............
1=a * (-2)³+4 * (-2) -3
1=-8a-8-3
8a=-11-1
8a=-12
a=-12;8
a=-1,5
............
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W(x) = a x^3 + 4x - b
W(0) = - 3
W( - 2) = 1
zatem
a*0^3 + 4*0 - b = - 3
a*(-2)^3 + 4*(-2) - b = 1
---------------------------------
b = 3
------------
- 8 a - 8 - 3 = 1
- 8 a = 12
a = - 12/8 = -1,5
----------------------
Odp. a = - 1,5; b = 3
==============================
-3=a * 0³+4 *0-b
-3=-0
b=3
.............
1=a * (-2)³+4 * (-2) -3
1=-8a-8-3
8a=-11-1
8a=-12
a=-12;8
a=-1,5
............