September 2018 1 91 Report

wyrażenie 2^{log_4(1+sin2x)} dla x\neq \frac{\pi}{4}+k\pi, jest równe

\sqrt{1+sin2x}

sinx+cosx

\sqrt{2}cosx(x+\frac{\pi}{4})

wartość bezwzględna z (sinx+cosx)


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