December 2018 1 44 Report
Wykaż, że:

 \frac{1}{24}+ \frac{1}{104} + \frac{1}{234}+...+ \frac{1}{(5n-2)(5n+3)} + \frac{1}{5(5n+3)}= \frac{1}{15}

Rozkładając na ułamki proste zapominam o czymś i wychodzi  \frac{1}{3}. Z góry dziękuję.
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