Wiedząc, że log12= a i log2= b, oblicz log90
log12=a log2=b a = log12 a = log(3*4) a = log3 + log4 a = log3 + log2² a = log3 + 2log2 a = log3 + 2b log3 = a - 2b log90 = log(10*9) = log10 + log9 = 1 + log3² = 1 + 2log3 log90 = 1 + 2(a - 2b) = 1 + 2a - 4b log90 = 1 + 2a - 4b
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log12=a
log2=b
a = log12
a = log(3*4)
a = log3 + log4
a = log3 + log2²
a = log3 + 2log2
a = log3 + 2b
log3 = a - 2b
log90 = log(10*9) = log10 + log9 = 1 + log3² = 1 + 2log3
log90 = 1 + 2(a - 2b) = 1 + 2a - 4b
log90 = 1 + 2a - 4b