Wiedząc, że α jest kątem ostrym oraz 4tgα= 3sin²α + 3cos²α oblicz wartość wyrażenia tgα+ctgα
4tga=3(sin^2a+cos^2a)
sin^2a+cos^2a=1
4tga=3
tga=3/4
tga=1/ctga
tga+ctga= 3/4+4/3=25/12=2 1/12
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4tga=3(sin^2a+cos^2a)
sin^2a+cos^2a=1
4tga=3
tga=3/4
tga=1/ctga
tga+ctga= 3/4+4/3=25/12=2 1/12