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z k.ata 30 wynika,że a√3:2=8
a√3=16
a=16√3:3
a=¹⁶/₃√3= bok BC
BOK DB=½ BC=⁸/₃√3
kat 45 wskazuje,że AD=H=8
zaś AC=a√2=8√2
obwód=8√2+8+⁸/₃√3+¹⁶/₃√3=8√2+8+8√3=8(√2+1+√3) j.