w ciągu geometrycznym a3=8, a7= ½ .Wyznacz pierwszy wyraz i iloraz tego ciągu.
a3 = 8 oraz a7 = 1/2 <-- wyrazy ciągu gepmetrycznego
Mamy
a3 = a1*q^2
a7 = a1*q^6
zatem a7 : a3 = a1*q^6 : a1*q^2 = q^4
ale a7 : a3 = (1/2) : 8 = 1/16
czyli q^4 = 1/16
q = 1/2
=======
a3 = a1*q^2 ---> a1 = a3 : q^2 = 8 : (1/2)^2 = 8 : (1/4) = 8 *4 = 32
Odp. a1 = 32; q = 1/2
==============================
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
a3 = 8 oraz a7 = 1/2 <-- wyrazy ciągu gepmetrycznego
Mamy
a3 = a1*q^2
a7 = a1*q^6
zatem a7 : a3 = a1*q^6 : a1*q^2 = q^4
ale a7 : a3 = (1/2) : 8 = 1/16
czyli q^4 = 1/16
q = 1/2
=======
a3 = a1*q^2 ---> a1 = a3 : q^2 = 8 : (1/2)^2 = 8 : (1/4) = 8 *4 = 32
Odp. a1 = 32; q = 1/2
==============================