¹⁴ ₇ N + ⁴ ₂ α = ¹⁷ O + ₁ p
¹⁴ ₇ N + n = ¹⁴ C + p
2. Ile cząstek α i β zostanie wyemitowanych w przypadku, gdy izotop ²³⁸ ₉₂
U przekształca się w izotop ²⁰⁶ ₈₂ U ?
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1)
¹⁴ ₇ N + ⁴ ₂ α = ¹⁷ ₈ O + ¹ ₁ p
¹⁴ ₇ N + ¹ ₀ n = ¹⁴ ₆ C + ¹₁ p
¹ ₀ n---neutron
¹₁ p---proton
2)
²³⁸ ₉₂ U----->8 ⁴ ₂ α + 6 ⁰ ₋₁ β + ²⁰⁶ ₈₂ Pb