Uzasadnij że dla a > 0 wartość wyrażenia ∛(√a)³·a√a ÷ a jest równa 1
(√a)³ = a√a ∛[(√a)³·a√a] ÷ a = ∛ (a√a·a√a) ÷ a
-
a√a·a√a = a ³
∛ (a√a·a√a) ÷ a = ∛ a ³ ÷ a -
∛ a ³ = a ∛ a ³ ÷ a = a ÷ a = 1
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(√a)³ = a√a
∛[(√a)³·a√a] ÷ a = ∛ (a√a·a√a) ÷ a
-
a√a·a√a = a ³
∛ (a√a·a√a) ÷ a = ∛ a ³ ÷ a
-
∛ a ³ = a
∛ a ³ ÷ a = a ÷ a = 1